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(C) The structure of the compound is $H_2C=C=CH-CHO$.$1$. The terminal $CH_2$ carbon is bonded to two hydrogens and one double bond,so it is $sp^2$ hy

Vedclass · Accepted Answer

$0-3-1$

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(C) The structure of the compound is $H_2C=C=CH-CHO$.$1$. The terminal $CH_2$ carbon is bonded to two hydrogens and one double bond,so it is $sp^2$ hybridized.$2$. The central carbon in the allene system $(C=C=C)$ is bonded to two double bonds,so it is $sp$ hybridized.$3$. The $CH$ carbon is bonded to one hydrogen,one double bond,and one single bond,so it is $sp^2$ hybridized.$4$. The carbonyl carbon $(CHO)$ is bonded to one hydrogen and one double bond,so it is $sp^2$ hybridized.Total count:$sp^3$ carbons: $0$$sp^2$ carbons: $3$$sp$ carbons: $1$Therefore,the correct sequence is $0-3-1$.

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

Similar Questions

Which of the following compounds do not have $sp^3$ carbon atom$(s)$?
$I$. Acetone
$II$. Acetic acid
$III$. Buta-$1,3$-diene
$IV$. Propyne
$V$. Naphthalene

The compound in which $C^*$ uses $sp^3$ hybrid orbitals for bond formation is

$CH_3-CH_2-CH=CH_2$ has hybridisation

Among the following compounds,which have more than one type of hybridization for carbon atoms?
$(i) CH_3CH_2CH_2CH_3$
$(ii) CH_3-CH=CH-CH_3$
$(iii) CH_2=CH-C\equiv CH$
$(iv) HC\equiv CH$

Number of $sp$ hybridised carbon atoms in the given compound is:
$CH_2 = CH - C \equiv C - CH_2 - CN$

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Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:$H_2C=C=CH-CHO$(Order: $sp^3 - sp^2 - sp$)